2*10^-3*x^2=0,05

Solution for 2*10^-3*x^2=0,05 equation:

2*10^-3x^2=0.05

We move all terms to the left:

2*10^-3x^2-(0.05)=0

We add all the numbers together, and all the variables

-3x^2+1.78250187627=0

a = -3; b = 0; c = +1.78250187627;
Δ = b2-4ac
Δ = 02-4·(-3)·1.78250187627
Δ = 21.3900225152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{21.3900225152}}{2*-3}=\frac{0-\sqrt{21.3900225152}}{-6}
=-\frac{\sqrt{}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{21.3900225152}}{2*-3}=\frac{0+\sqrt{21.3900225152}}{-6}
=\frac{\sqrt{}}{-6}
$